"""
    Darin Brezeale
    August 22, 2010

    prompt the user for a year, then determine if it is a leap year
"""

year = input("Enter a year:  ")

# version 1
if  year%4 == 0 :
    if year%100 == 0 :
        if year%400 == 0 :
            print "version 1: ", year, "is a leap year"
        else:
            print "version 1: ", year, "is NOT a leap year"
    else:
        print "version 1: ", year, "is a leap year"
else:
    print "version 1: ", year, "is NOT a leap year"