"""
    Darin Brezeale
    August 22, 2010

    prompt the user for a year, then determine if it is a leap year
"""

year_text = input("Enter a year:  ")
year = int(year_text)

# version 1
if  year%4 == 0 :
    if year%100 == 0 :
        if year%400 == 0 :
            print("version 1: ", year, "is a leap year")
        else:
            print("version 1: ", year, "is NOT a leap year")
    else:
        print("version 1: ", year, "is a leap year")
else:
    print("version 1: ", year, "is NOT a leap year")